So long as the <br/> elements are children of the <p> element (not
descendants), you can use

<xsl:for-each-group group-starting-with="br">

This will include the br element as a member of the group, but you can
easily lose it using

current-group()[not(self::br)]

(You can use group-ending-with="br" as well, but if you drop the br elements
the effect is identical).

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Georges Schmitz [mailto:georges.schmitz@xxxxxxxxx] 
> Sent: 07 November 2006 13:47
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  "Line"-Tokenizing at <br/> in xhtml 
> 
> Tokenizing a string at LFs and putting <br/> in  place of 
> them is well known to me (in XSLT2.0), but for the moment I'm 
> stuck with the other way round.
> 
> I have something like this (xhtml):
> 
>     <p>blabla blabla <br/>
>     blabla blabla blabla <br/>
>     blabla <b>blabla</b> blabla <br/>
>     blabla blabla blabla</p>
> 
> I need to have access to every single "line" (terminated by 
> <br/>), preserving the mixed content of the lines.
> 
>    1. The tokenize() function as well as the analyze-string 
> method only
>       operate on strings, not on mixed content.
>    2. <for-each select=".//text()"> (just posted some days 
> ago) doesn't
>       work because of line 3, and
>    3. <xsl:for-each select="br">
>         <xsl:value-of select="preceding-sibling::text()[1]"/>
>       </xsl:for-each>
>       a) doesn't work because of line 3
>       b) I would have to fetch the last line separately
> 
> Thanks for any advise,
> Georges Schmitz