Subject: RE: Identify transform with disabled output escaping
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 15 Nov 2006 17:56:29 -0000
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There are two common forms of identity transform. The one with
<xsl:template match="node()|@*">
relies on xsl:copy to copy the text nodes
The one with <xsl:template match="*"> relies on the built-in template rule
for text nodes to copy the text nodes.
But in either case, you can write a template rule for text nodes:
<xsl:template match="text()" priority="10">
<xsl:value-of select="." disable-output-escaping="yes"/>
</xsl:template>
that will override the default.
Though why on earth you would want to disable output escaping on all the
text in your document defeats me.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Peter Szinek [mailto:peter@xxxxxxxxxxxxxxxx]
> Sent: 15 November 2006 18:04
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Identify transform with disabled output escaping
>
> Hello all,
>
> I have been browsing the archives for at last 2 hours and
> could not find the answer - though it seems so trivial.
>
> I have found some older messages claiming that the identify
> transformation can not be done without xsl:copy. However,
> disable-output-escaping is valid for xsl:value and xsl:text
> only (i.e. not for xsl:copy). For me, these two statements
> imply that the identify transformation can not be done with
> output escaping disabled.
>
> Is there a workaround for this?
>
> Thanks,
> Peter
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Michael Kay - 15 Nov 2006 17:56:53 -0000 <=
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