The transform requires to modify only the "environment" element, and
keeping rest of the structure same. To solve this problem, you require
an identity transform template, and a template to process the
"environment" element.

<xsl:template match="node() | @*">
 <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
 </xsl:copy>
</xsl:template>

<xsl:template match="environment">
  <environment>
    <variable id="SAROOTDIR" value="D:\Dir1"/>
    <variable id="SADATADIR" value="D:\Dir2"/>
  </environment>
</xsl:template>

Hi:

I have the following input xml document, I need to write an xsl to transform
it to the output xml document.

Input xml document -

<?xml version = '1.0' encoding = 'UTF-8'?>
<test xmlns="blabla">
<comp id="New">
<process-type id="home" module-id="TESTER" status="enabled">
<environment>
</environment>
</process-type>
</comp>
</test>

Output xml document -

<?xml version = '1.0' encoding = 'UTF-8'?>
<test xmlns="blabla">
<comp id="New">
<process-type id="home" module-id="TESTER" status="enabled">
<environment>
<variable id="SAROOTDIR" value="D:\Dir1"/>
<variable id="SADATADIR" value="D:\Dir2"/>
</environment>
</process-type>
</comp>
</test>

Can someone please help write an xsl to transform the above input xml
document into the output xml document?

Thanks much!

--
Regards,
Mukul Gandhi