Subject: RE: Is it possible to create xsl:sort from input parameters using XSLT 2.0 (Saxon)?
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Mon, 31 Jul 2006 17:52:53 +0100
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> <xsl:param name="sortField"/>
>
> And into this param i pass the XML:
>
> <SortFields>
> <SortField>
> <Sort>lendername</Sort>
> <Order>ascending</Order>
> <DataType>text</DataType>
> <CaseOrder>lowercasefirst</CaseOrder>
> </SortField>
> </SortFields>
>
>
> rather than use 12 parameters (four for each <xsl:sort/>), I
> had hoped that using this XML I would be able to read the
> values out like so:
>
> <xsl:sort select="$sortField/SortField[1]/Sort"
> order="{$sortField/SortField[1]/Order}"/>
You want $sortField/SortFields/SortField[1]/Order
>
>
> As far as I can tell the order attribute should read
> "acsending" out of the XML but I've no real way of finding
> out what it is reading.
Take a look at the trace() function, or simply do <xsl:copy-of
select="$sortField"/>.
Better still, write a little schema for this XML document and make your
stylesheet schema-aware, and then the error will be reported to you at
compile time.
Michael Kay
http://www.saxonica.com/
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