Subject: Re: Recursive counting
From: Steve <subsume@xxxxxxxxx>
Date: Wed, 19 Jul 2006 11:40:47 -0400
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Much appreciated, but I'm still on the 1.0 train. Havin' trouble using
DLLs for Saxon.NET without going Visual Studio crazy. =)
Thanks tho,
-S
On 7/19/06, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> Well after success with my first recursive template I was all
> set to make one of my own, but now shamefully am coming to
> the list for advice over something that appears quite simple.
First thing is to recognize this as a grouping problem. For each distinct
value of @type you need to do something.
In XSLT 2.0:
<xsl:for-each-group select="/*/options/o" group-by="@type">
<xsl:sort select="current-grouping-key()"/>
<out type="{current-grouping-key()}"
count="{count(/*/person[@pref=current-group()]}"/>
</xsl:for-each-group>
>
> XML ------->
>
> <options>
> <o type="A">who</o>
> <o type="A">what</o>
> <o type="A">when</o>
> <o type="B">how</o>
> <o type="B">nexus</o>
> <o type="B">triumph</o>
> <o type="C">alligator</o>
> <o type="C">spurn</o>
> </option>
>
> <people>
> <person pref="who" />
> <person pref="nexus" />
> <person pref="how" />
> <person pref="alligator" />
> <person pref="spurn" />
> <person pref="triumph" />
> .... etc ....
> </people>
>
>
> Desired output ------->
>
> <!-- @count corresponds to number of times the preference
> appeared among the list of <people> --->
>
> <out type="A" count="1" />
> <out type="B" count="3" />
> <out type="C" count="1" />
>
>
> Stipulation: --------->
>
> <out>'s must be sorted alphabetically, regardless of <option> order.
| Current Thread |
Michael Kay - 19 Jul 2006 15:38:55 -0000
- Steve - 19 Jul 2006 15:41:03 -0000 <=
Steve - 19 Jul 2006 19:42:00 -0000
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