Subject: RE: Recursively merge (aggregate) and traverse DOM trees (XML files)?
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Tue, 20 Jun 2006 08:15:44 +0100
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Your stylesheet needs to include within it an instruction such as
<xsl:apply-templates select="document(@url)"/>
to dereference the links and recursively process the referenced document.
I don't know what this is supposed to be:
<?xml versionfiltered="1.0" encoding="UTF-8"?>
but it isn't XML.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Laky Tang [mailto:tulaky@xxxxxxxxx]
> Sent: 20 June 2006 03:46
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Recursively merge (aggregate) and traverse DOM
> trees (XML files)?
>
> I am trying to recursively merge a tree of XML files and then
> apply some templates to it. I googled and also searched this
> mailing list but did not find any help. I hope this is
> possible using XSLT. Can somebody please point me in the
> right direction?
>
> Here is a sample of the input files and desired output. I
> tried a sample.xsl (see below)which only goes thru the root
> file, but need help in making it recursively go thru all the
> linked files as well.
>
> Thanks in advance,
> Laky, Tang
> -----------------
> sample1.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?>
> <?xml-stylesheet type="text/xsl" href="sample.xsl"?> <a> <b p
> ="key1" q="2"> xxx </b> <b url = "sample2.xml"></b> <b p
> ="key10" q ="27">yyyy</b> </a>
>
> sample2.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
> ="key4" q="22"> xxx2 </b> <b url = "sample3.xml"></b> <b p
> ="key7" q ="37">yyyy2</b> <b url = "sample4.xml"></b> </a>
>
> sample3.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
> ="key5" q="23"> xxx3 </b> <b p ="key6" q ="26">yyyy3</b> </a>
>
> sample4.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
> ="key8" q="24"> xxx4 </b> <b p ="key9" q ="25">yyyy4</b> </a>
>
> sample.xsl :
> <?xml versionfiltered="1.0" encoding="UTF-8"?>
> <xsl:stylesheet versionfiltered="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:fo="http://www.w3.org/1999/XSL/Format"
> xmlns:xs="http://www.w3.org/2001/XMLSchema"
> xmlns:fn="http://www.w3.org/2005/02/xpath-functions"
> xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes"
> xmlns:xlink="http://www.w3.org/1999/xlink">
> <xsl:template match="/">
> <html>
> <head>
> <title>Sample</title>
> </head>
> <h1>
> <center>
> </center>
> </h1>
> <p/>
> <xsl:for-each xml:space="default" select="param">
> <xsl:value-of select="."/> </xsl:for-each> <table border="2"
> bgcolor="yellow"> <tr> <th>P</th> <th>Q</th> <th>text</th>
> </tr> <xsl:for-each select="//b"> <tr> <td> <xsl:value-of
> select="@p"/> </td> <td> <xsl:value-of select="@q"/> </td>
> <td> <xsl:value-of select="."/> </td> </tr> </xsl:for-each>
> </table> </html> </xsl:template> </xsl:stylesheet>
>
>
> Desired output (preferably as a html table):
>
> P Q text
> key1 2 xxx
> key4 22 Xxx2
> key5 23 xxx3
> key6 26 yyy3
> Key7 37 yyy2
> key8 24 xxx4
> key9 25 yyy4
> key10 27 yyyy
>
>
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