You could ask this equally of XSLT 1.0.

You haven't defined a template that matches idnr, so your stylesheet behaves
as if you had defined

<xsl:template match="idnr">
  <xsl:apply-templates/>
</xsl:template>

Look in the spec for "built-in template rules".

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Georg Hohmann [mailto:georg.hohmann@xxxxxxxxx] 
> Sent: 23 May 2006 13:39
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  XSLT2 processing question
> 
> Hello,
> 
> till today i thought that i was no beginner with xslt anymore 
> but now i'm not sure about. I thought i knew how xsl 
> processes data but that was wrong (i guess). I read many 
> basic informations about the processing structure but i 
> didn't get right idea what in my thinking is wrong. So i bend 
> my knees and ask the experts ;-)
> 
> What i got is something like this as the source:
> ---------------------------------------------------------------------
> <?xml version="1.0" encoding="UTF-8"?>
> <customers>
>    <info>This is data about customers</info>
>    <person>
>       <name>
>             <first>John</first>
>             <last>Doe</last>
>       </name>
>       <idnr>123</idnr>
>    </person>
>    <person>
>       <name>
>             <first>Tom</first>
>             <last>Test</last>
>       </name>
>       <idnr>456</idnr>
>    </person>
>    <person>
>       <name>
>             <first>Edna</first>
>             <last>Example</last>
>       </name>
>       <idnr>789</idnr>
>    </person>
> </customers>
> ---------------------------------------------------------------------
> 
> My Stylesheet looks like this:
> ---------------------------------------------------------------------
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="2.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>    <xsl:output name="out" method="xml" version="1.0" encoding="UTF-8"
> indent="yes"/>
>    <xsl:template match="/">
>       <xsl:result-document format="out" href="result.xml">
>          <adress>
>             <xsl:apply-templates/>
>          </adress>
>       </xsl:result-document>
>    </xsl:template>
>    <xsl:template match="//name">
>       <firstname>
>          <xsl:value-of select="first"/>
>       </firstname>
>    </xsl:template>
> </xsl:stylesheet>
> ---------------------------------------------------------------------
> 
> What i *want* to have is this:
> ---------------------------------------------------------------------
> <?xml version="1.0" encoding="UTF-8"?>
>    <adress>
>       <firstname>John<firstname>
>       <firstname>Tom<firstname>
>       <firstname>Edna<firstname>
>    </adress>
> ---------------------------------------------------------------------
> 
> But the result i get from my stylesheet is this:
> ---------------------------------------------------------------------
> <?xml version="1.0" encoding="UTF-8"?>
> <adress>
>    This is data about customers
> 
>       <firstname>John</firstname>
>       123
> 
> 
>       <firstname>Tom</firstname>
>       456
> 
> 
>       <firstname>Edna</firstname>
>       789
> 
> </adress>
> ---------------------------------------------------------------------
> 
> What am I doing wrong? I thought the stylesheet would do the
> following: Go to the root element (match="/"), generate my root
> ("adress") and add the results of the following template 
> (apply-templates). The next template searches for the node "name"
> everyware in the source ("//name"), and for each nodes it 
> finds it appends a node called "firstname" with the value of "first".
> 
> Well, obviously this is not (exactly) what it does. Why are 
> the values of "info" and "idnr" also in the output? I know 
> this is an issue about how xslt processes data and it's a 
> real beginner scenario, so i'm sorry to waste your time with 
> it. I'm not (only) interested in the right solution to get 
> the result i want but also for an explanation of where my 
> thinking is wrong.
> 
> I would be happy if someone could give me a hint ...
> 
> Regards,
> G. Hohmann