See http://www.dpawson.co.uk/xsl/sect2/N2018.html#d3114e487

In your case step 2 is to apply the translate() function.

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: Markus Gamperl [mailto:markus.gamperl@xxxxxx] 
> Sent: 27 April 2006 15:44
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  sum up float values problem
> 
> Dear experts!
> 
> XSL 1.0:
> I have got the following XML:
> 
> <POSITION>
>  <LSUM>14,68</LSUM>
>  <LSUM>321</LSUM>
>  <LSUM>13</LSUM>
>  <LSUM>100,6</LSUM>
> ...
> </POSITION>
> 
> I want to sum up all my LSUM elements. When I do a 
> sum(//LSUM) I only get a number value, not a float value... 
> This would work if the float values are separated with a '.' 
> not a ',' (eg. 14.68). But I get the values separated with a ','...
> 
> So I had following idea:
> sum(translate(//LSUM,',','.'))
> 
> But the translate function only returns the first node 
> (14.68) of the nodeset...
> 
> Do you have an idea how to solve this issue simply?
> 
> Thanks
> Markus 
> 
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