Cheers,
Wendell

I am writing an XSL:FO document that will create a pdf document. One
chapter will contain an "example XML".

I access the XML file by a variable using document() function, and so
far so good. I now want to list the whole file tags, names, values and
all, pereferrably also indentaions.

When I try to list the whole XML file firstly, I try:

<xsl:for-each select="$SourceMetadata/*">
<!--List the XML file-->
<xsl:copy-of select="." />
</xsl:for-each>

This results in an error message saying: "Element name :
BusinessObjectName.(namespace = Null) Source context
unavailable.Unsupported element encountered".

The BusinessObjectName is the first element in the XML file.
The XML file does not contain any namespace.

I then try to add attribute copy-namespaces=No, then the parser says it
is wrong attribute for copy-of. Parser = Apache FOP.bat.

I change the code to:

<xsl:for-each select="$SourceMetadata/*">
<!--List the XML file-->
<xsl:copy-of select="node()" />
</xsl:for-each>

Now I get all element values in a row. No element names and no tags.

I then change to:

<xsl:for-each select="$SourceMetadata/*">
<!--List the XML file-->
<xsl:copy-of select="name()/>
</xsl:for-each>

I then get all tag names in a row, no values, no tags.

What can I do?

======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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