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At 2006-03-24 08:13 +0800, rostom aghanian wrote:
I have multiple xsl:for-each loops where I am trying to output the position of XPath defines the position() function as returning the current node's position in the current context as calculated by the evaluation's context. This means that each time you do a select= it returns a current node list and your position in that list *always* starts at 1. According to your evidence, the processor is broken ... perhaps you are misinterpreting what you have from what you are seeing. I hope this helps. . . . . . . . . Ken -- Upcoming XSLT/XSL-FO hands-on courses: Washington,DC 2006-06-12/16 World-wide on-site corporate, govt. & user group XML/XSL training. G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) Male Cancer Awareness Aug'05 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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