Thank you. I had been fighting that one for days.


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Date: Tue, 28 Mar 2006 00:39:05 +0100
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Subject: RE:  Confusion about xsl:param and key()

So long as the value will always be an element name, use

*[name()=$groupBy]

Michael Kay
http://www.saxonica.com/