> I think that I am still correct in saying that there is no intrinsic
> way of stating that eg. ' ' (space) equals & #x20; (and should
> therefore be replaces with %20). This part would have to be done using
> a choose-when expression, I think.

Well, you could do

string-length(substring-before("all-the-unicode-characters-in-sequence"))

which is a little better than that, but still pretty horrendous.

Michael Kay
http://www.saxonica.com/