Hmm I see.  The only problem is there could be more tags like
WAAUXCallerID, which shouldn't be counted.  So I only can rely on
WAAUXxx... (where xx can be any number)

However again repetitions aren't allowed.

e.g.

WAAUX01
WAAUX01
WAAUXWithholdNumberAllCalls
WAAUX04
WAAUXCallerID


Should output a 2.  I am not sure if this problem is solvable at all.

Besides I have to stick with XSLT 1.0.

Regards
Houman




-----Original Message-----
From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
Sent: 05 October 2005 17:02
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Wildcard problem

In 2.0 you can use regular expressions. Here I think you just want

count(*[starts-with(name(),'WAAUX')]) -
count(*[starts-with(name(),'WAAUXCallerID')])

Michael Kay
http://www.saxonica.com/