Subject: Namespace on output node but not not in source
From: António Mota <amsmota@xxxxxxxxx>
Date: Tue, 18 Oct 2005 00:58:40 +0100
|
Hi:
I have a xsl with a namespace declared
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
so i can make some lookups on a xsd file
<xsl:variable name="tipo"
select="$schema/xs:schema/xs:element[@name=$nome]/@type"/>
and that's all i do, i don't copy any node from $schema to the output tree.
However, this
<xsl:template match="/">
<table>
<xsl:apply-templates
select="(//Menu)[position()=$pos]"/>
</table>
</xsl:template>
produces a
<table xmlns:xs="http://www.w3.org/2001/XMLSchema">
<...>
</table>
and i don't understand why, and i don't want it there.
I add a exclude-result-prefixes="xs" but it seems it makes no diference.
Why is this?
Thanks.
|