Thanks Wendell,

The way I'm looking to split the items into groups is as follows.

1 to 5 items - 1 group
6 to 10 items - 2 groups
11 to 15 items - 3 groups
16 - 20 items - 4 groups
21 - 25 items - 5 groups

So the number of groups will in fact depend on the number of <source>
nodes in the XML file. The <source> nodes will are already in the
correct order in the XML file so I don't need to sort them in any
other way in the XSL.

Cheers,
Mike.


On 10/31/05, Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:
> Mike,
>
> The one thing you don't say is by what rule you would like the
> splitting to occur (you only say "into two or more groups").
>
> If you wanted to split into exactly two groups, you could do:
>
> <xsl:template match="sources">
>    <div>
>      <xsl:apply-templates
>        select="source[position() &lt;= (last() div 2)"/>
>    </div>
>    <div>
>      <xsl:apply-templates
>        select="source[position() &gt; (last() div 2)"/>
>    </div>
> </xsl:template>
>
> Notice if you have an odd number of source element children, the
> first group will be short one item.
>
> There are other methods available for grouping them differently and
> even according to data-driven criteria, for example if you need to
> determine dynamically how many groups you want.