I confirm Michael Kay's remark. If your parameter's name (as defined by the name attribute of the xsl:param element) is "Date", then your command line should read:

	msxsl.exe testme.xml myfix.xsl Date="2005-01-01" -o out.html
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     stuart arnold <stuart.arnold@xxxxxxxxxxx>
Sent:     Thu, 22 Sep 2005 18:59:16 -0400
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE:  % in xslt printing as ?

I treied that, I guess I'm missing something.

I'm calling at:
	msxsl.exe testme.xml myfix.xsl param="2005-01-01" -o out.html

In the XSL, what should I have, I mean, how does it know that that param
goes with what, eg
	<xsl:param name="Date" />

Should I have more on the command line or the XSL?

Thanks for the reply and any help.

-----Original Message-----
From: Michael Kay [mailto:mike@xxxxxxxxxxxx] 
Sent: Thursday, September 22, 2005 6:38 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  % in xslt printing as ?


> 
> I'm trying to pass a variable to my xsl processor as well, but I don't

> know how to recive it in the XSL. What xsl command do I use?

Use <xsl:param name="nnnn"/> as a top-level element (a child of
xsl:stylesheet). Then refer to the parameter just like a variable, as
$nnnn. The way you actually supply the parameter a value depends on the
processor API you are using.

Michael Kay
http://www.saxonica.com/