Thank you Jay and everyone else who responded. This is a good start for me. In fact last couple of
days I've been trying to use this solution.
Anupam.

--- Jay Bryant <jay@xxxxxxxxxxxx> wrote:

> Welcome to the list.
> 
> I've been on the list long enough to tell you that this topic is not that
> common (but not unknown, either). We tend to get grumpy when the same
> question gets asked three times in two days (as happened over the last two
> days), but this one hasn't turned up in a while.
> 
> You're basically up against a form of cross-referencing, which XSLT does
> well.
> 
> To handle it, you set up a template to match A and a template that handles
> enough of B to ensure that A gets handled. Then you write the A template to
> process the parts of the A_DEC node that you want. Here's how:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> 
>   <xsl:template match="A">
>     <xsl:variable name="thisname" select="@name"/>
>     <xsl:variable name="thisref" select="@ref"/>
>     A.doc = <xsl:value-of select="doc"/>
>     A.v1 = <xsl:value-of select="//*[local-name() = $thisref][@name =
> $thisname]/v1"/>
>   </xsl:template>
> 
>   <xsl:template match="A_DEC"/>
> 
>   <xsl:template match="B">
>     <xsl:apply-templates select="A"/>
>   </xsl:template>
> 
> </xsl:stylesheet>
> 
> I tested that with Saxon 8 and got the results you wanted.
> 
> If you can, avoid using the // path option. It's the most expensive thing
> you can do. Still, this kind of searching can be one of the times that // is
> the way to go.
> 
> Let us know what other issues we can address. You'll find the list pretty
> helpful, provided you take the time to ask good questions, as you did here.
> 
> Happy XSLTing.
> 
> Jay Bryant
> Bryant Communication Services
> 
> ----- Original Message ----- 
> From: "Agnisys Technology (P) Ltd." <agnisys@xxxxxxxxx>
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Friday, August 26, 2005 10:43 PM
> Subject:  Subtype/inheritance in XML, how does XSLT handle it?
> 
> 
> > Hi,
> >   Can XSL handle subtypes/inheritance in XML?
> >
> > I have an XML document that "declares" a type "someA" and then uses it, as
> follows:
> > <top>
> >   <A_DEC name="someA">
> >     <doc>  aaaaaaa </doc>
> >     <v1> 100 </v1>
> >   </A_DEC>
> >
> >   <B>
> >      <A ref="A_DEC" name="someA">
> >         <doc>  bbb </doc>
> >      </A>
> >   </B>
> > </top>
> > ---------------------
> > I want this to be transformed into :
> > A.doc   = bbb
> > A.v1    = 100
> > ---------------------
> > Note that doc value is overridden from the XML doc and the v1 value is
> used from the original
> > definition.
> >
> > How do I make XSLT use the entity "A_DEC" when it encounters A?
> >
> > I'm designing the XML language, so I have the flexibility. If this kind of
> problem is solved
> > differently in XML, please advice.
> >
> > I would much appreciate even partial answers or any pointers.
> > Thanks,
> > Anupam.
> >
> > P.S. I'm new to XML, and to this list, please excuse if this question has
> been answered before.
> > Unfortunately I couldn't find the answer when I searched.
> >
> >
> >
> >
> >
> > ____________________________________________________
> > Start your day with Yahoo! - make it your home page
> > http://www.yahoo.com/r/hs
> 
> 



		
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