Your stylesheet probably doesn't need to declare this namespace, so just
delete it: it's needed only when the target vocabulary is XSL-FO, but some
XSLT editors seem to declare it for you by default.

If you do need a namespace in your stylesheet that you don't want copied
into the result document, use the exclude-result-prefixes attribute to
exclude it.

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: ChandraShekar, A [mailto:ChandraShekar.A@xxxxxxxxxxx] 
> Sent: 17 August 2005 12:17
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  Converting XML to XML
> 
>  Hello,
> 
>    I have written small program to convert XML to XML.
>    But each XML tag contains
> xmlns:fo="http://www.w3.org/1999/XSL/Format" as a attribute. How to
> avoid this?
> 
> 
> -----Original Message-----
> From: Michael Kay [mailto:mike@xxxxxxxxxxxx] 
> Sent: Wednesday, August 17, 2005 4:40 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  Converting XML to XML
> 
>  
> > 
> > 	Is it possible to convert XML to XML using XSLT ?
> 
> Yes, that's precisely what XSLT does.
> 
> > 
> > In my case Source is :
> > <a>
> > <b>
> > </b>
> > <c>
> > </c>
> > </a>
> > 
> > Destination is :
> > 
> > <x>
> > <y>
> > </y>
> > <z>
> > </z>
> > </x>
> > 
> > Please provide me some sample code.
> > 	
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> 
> <xsl:template match="a">
>   <x><xsl:apply-templates/></x>
> </xsl:template>
> 
> <xsl:template match="b">
>   <y><xsl:apply-templates/></y>
> </xsl:template>
> 
> <xsl:template match="c">
>   <z><xsl:apply-templates/></z>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
> 
> Michael Kay
> http://www.saxonica.com/