Cart
[Home] [By Thread] [By Date] [Recent Entries]
I'd like to return a sub-path which is selected by a parameter to the XSLT. Something like:- <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:param name="path" select="'/part[1]'"/> <!-- default value --> <xsl:template match="$path"> <xsl:apply-templates mode="copy"/> </xsl:template> <xsl:template match="@*|node()" mode="copy"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="copy"/> </xsl:copy> </xsl:template> </xsl:stylesheet> What is the best way of going about this? Thanks. -- Steve Lloyd XML Developer, Publications group, International Baccalaureate Organization Email: steve.lloyd[at]ibo.org Tel: +44 (29) 2054 7869 WWW: http://www.ibo.org
|
