Subject: Re: Problem with parsing nodes saved in variable
From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx>
Date: Wed, 13 Jul 2005 00:39:11 -0700 (PDT)
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You can use the node-set function. With XSLT 1.0, its
not part of the language. Nearly all XSLT 1.0
compliant processors support node-set, notably
Xalan-J, Saxon and MSXSL.
With XSLT 2.0 there is no need to use node-set
function. The variable can be manipulated directly
with XPath syntax. Saxon 8.x provides the
implementation.
Regards,
Mukul
--- Lakshmi narayana <lchintala@xxxxxxxxxxxx> wrote:
>
> Hi,
> This is my xml file.
> <A1 name="(R) MSH" sequence="1"
> Description="optional" >
> <B1 name="B1" sequence="5"
> order="first"></B1>
> <B2 name="B1" sequence="102" order="first"
> >
> <C1 name="C1" sequence="201"
> order="Sec" ></C1>
> <C2 name="C2" sequence="202"
> order="Sec" >
> <C3/>
> <D1 name="D1"
> sequence="11" Max="1"
> Reference="Trr" Predicate="" />
> </C2>
> </B2>
> </A1>
>
> I wrote an XSLT which dynamically adds attibute
> named Type to each node. I
> wrote the XSLT like this.
>
> <xsl:template match="/">
> <xsl:variable name="myVar">
> <xsl:apply-templates />
> </xsl:variable>
> </xsl:template>
> <xsl:template match="/A1">
> <xsl:element name="IEElement">
> <xsl:attribute name="Type">
> <xsl:text>A-Type</xsl:text>
> </xsl:attribute>
> </xsl:element>
> </xsl:template>
> <xsl:template match="/B1">
> <xsl:element name="IEElement">
> <xsl:attribute name="Type">
> <xsl:text>B-Type</xsl:text>
> </xsl:attribute>
> </xsl:element>
> </xsl:template>
>
> In the above XSLT, how can I parse through each node
> saved in variable and
> access the dynamically created attribute 'Type'.
> Based on that,
> I want to do some processing.
>
> Thanks,
> Laxmi Narayana
>
>
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