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Wendell,
You're right that what I posted outputs nearly-the-right-thing but for the wrong reasons. The original problem asked (I think), given:
output:
Namely, output those sub_* which have more than 1 elem_* children named the same; also output the elem_* children. --A _________________________________________________________________ Dont just search. Find. Check out the new MSN Search! http://search.msn.click-url.com/go/onm00200636ave/direct/01/
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