The biggest difference with not() is that it will first check for existence
the node and might fail on that account - not because the values are
different.

But I think you can do a simpler test for your needs - how about this:

<xsl:if test="count(row/x[. != 0]) &gt; 0)">
	<xsl:message>Error<xsl:message>
</xsl:if>

-----Original Message-----
From: Jaime Stuardo [mailto:jstuardo@xxxxxxxxxxx]
Sent: Wednesday, June 08, 2005 10:12 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  (correction)  differences between x != 0 and not(x = 0)

Sorry, this is what to accomplish:

1.
<row>
  <x>0</x>
</row>
<row>
  <x>4</x>
</row>
<row>
  <x>0</x>
</row>

The test should return FALSE

2.
<row>
  <x>0</x>
</row>
<row>
  <x>0</x>
</row>
<row>
  <x>0</x>
</row>

The test should return TRUE.

That is, when ALL nodes have value of 0, I have to do something, and when at
least one x has a value different from 0, I want to do other thing. I want to
use <xsl:if>, not <xsl:choose>

Thanks
Jaime





-----Mensaje original-----
De: Jaime Stuardo
Enviado el: Miircoles, 08 de Junio de 2005 10:03
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Asunto:  differences between x != 0 and not(x = 0)

Hi all..

I always forgot this thing.

If I want to test that all nodes has value different from 0, I have to
use x!=0 or not(x=0) ?

For example,

<row>
  <x>0</x>
</row>
<row>
  <x>4</x>
</row>
<row>
  <x>0</x>
</row>

The test for the above example should return TRUE.

<row>
  <x>0</x>
</row>
<row>
  <x>0</x>
</row>
<row>
  <x>0</x>
</row>

The test for the above example should return FALSE.

Thanks
Jaime