RE: [xsl] select a node: child of an ancestor

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Subject: RE: select a node: child of an ancestor
From: "Aron Bock" <aronbock@xxxxxxxxxxx>
Date: Fri, 20 May 2005 04:42:19 +0000

Anthony, just your luck there've been at least 3 posts today about just this business of determining some property of a "related" node.

So, this XML (yours, extended):

<data>
<LeftNavTree n="1">
 <LeftNavParamList>
   <SelectedNode>Link 1.1.1</SelectedNode>
 </LeftNavParamList>
 <TreeNodeList>
   <TreeNode>
     <NodeID>Link 1</NodeID>
     <NodeContent>...</NodeContent>
     <TreeNodeList>
       <TreeNode>
         <NodeID>Link 1.1</NodeID>
         <NodeContent>...</NodeContent>
         <TreeNodeList>
         <TreeNode>
           <NodeID>Link 1.1.1</NodeID>
           <NodeContent>...</NodeContent>
         </TreeNode>
     </TreeNodeList>
   </TreeNode>
  </TreeNodeList>
 </TreeNode>
</TreeNodeList>
</LeftNavTree>

<LeftNavTree n="2">
 <LeftNavParamList>
   <SelectedNode>Link 2.2.2</SelectedNode>
 </LeftNavParamList>
 <TreeNodeList>
   <TreeNode>
     <NodeID>Link 2</NodeID>
     <NodeContent>...</NodeContent>
   </TreeNode>
  </TreeNodeList>
</LeftNavTree>
</data>

With this XSL:

<?xml version="1.0" encoding="iso8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/>

   <xsl:template match="/">
       <data>
       <xsl:apply-templates select="//NodeID"/>
       </data>
   </xsl:template>

<xsl:template match="NodeID"> <xsl:copy> <xsl:attribute name="SelectedNode"> <xsl:value-of select="ancestor::LeftNavTree//SelectedNode[1]"/> </xsl:attribute> <xsl:value-of select="."/> </xsl:copy> </xsl:template>

</xsl:stylesheet>

Yields this:

<?xml version="1.0" encoding="UTF-8"?>
<data>
 <NodeID SelectedNode="Link 1.1.1">Link 1</NodeID>
 <NodeID SelectedNode="Link 1.1.1">Link 1.1</NodeID>
 <NodeID SelectedNode="Link 1.1.1">Link 1.1.1</NodeID>
 <NodeID SelectedNode="Link 2.2.2">Link 2</NodeID>
</data>

Of course, you could optimize this quite a few ways, but you get the idea.

Regards,

--A

From: Anthony <apwebdesign@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  select a node: child of an ancestor
Date: Thu, 19 May 2005 16:55:51 -0700 (PDT)

I have the following xml tree, in which I need to
compare the value of <SelectedNode> with <NodeId>
while iterating:


<LeftNavTree>
  <LeftNavParamList>
    <SelectedNode>Link 1.1.1<</SelectedNode>
  </LeftNavParamList>
  <TreeNodeList>
    <TreeNode>
      <NodeID>Link 1</NodeID>
      <NodeContent>...</NodeContent>
      <TreeNodeList>
        <TreeNode>
          <NodeID>Link 1.1</NodeID>
          <NodeContent>...</NodeContent>
          <TreeNodeList>
          <TreeNode>
            <NodeID>Link 1.1.1</NodeID>
            <NodeContent>...</NodeContent>
          </TreeNode>
      </TreeNodeList>
    </TreeNode>
   </TreeNodeList>
  </TreeNode>
</TreeNodeList>
</LeftNavTree>

There could be more than one LeftNavTree, so
originally I was using this xpath:
//p:LeftNavTree/p:LeftNavParamList/p:SelectedNode

But it's concatonating the values of SelectedNode from
both LeftNavTree's. I need an xpath expression that
will grab "the SelectedNode element which is a
descendent of the ancestor LeftNavTree element for the
current node".

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Current Thread
select a node: child of an ancestor Anthony - 19 May 2005 23:56:14 -0000 Aron Bock - 20 May 2005 04:48:08 -0000 <= Anthony - 20 May 2005 04:48:33 -0000 Aron Bock - 20 May 2005 04:58:57 -0000 Amburose - 20 May 2005 06:19:19 -0000 Michael Kay - 20 May 2005 13:27:51 -0000

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