This way might seem a little strange, but should work:

At the top-level of your stylesheet specify:

   <xsl:decimal-format name="time" grouping-separator=":"/>

then where you want to do the conversion write:

   <xsl:value-of select="format-number(., '00:00', 'time')"/>

Not tested.

Michael Kay
http://www.saxonica.com/

 

> -----Original Message-----
> From: Ahsan Ali [mailto:doubleletter@xxxxxxxxx] 
> Sent: 29 May 2005 15:35
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  Q - Parsing & Manipulating Strings from XSL
> 
> Dear Michael,
> 
> Thanks for your quick & helpful reply. To answer your question: 
> 
> If the time is 12:45 it is returned as 1245.
> If it is 01:50 it is returned as 150
> If it is 00:45 it is returned 45
> if it is 00:04 it is returned as 4 !
> 
> So that's why I want to pad the beginning of string with 0s until its
> length is 4.
> 
> Its a strange way to do it, but as I said, I have to make the 
> best of it.
> 
> Also, I'm sorry to say I'm not very familiar with XQuery... what does
> $in have to be replaced with ? I'm getting an error.. FYI, the data is
> given as <JrnyTm>150</JrnyTm>
> 
> Best Regards,
> 
> Ahsan
> 
> On 5/29/05, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > >  A soap response contains a complex hierarchy of data, in 
> which, if
> > > the departure time is 00:45 hours then it is represented 
> as 45 ! To
> > > make matters worse, the schema defines it as a string. I have no
> > > influence over the schema since I'm querying a 
> webservice. So I need
> > > to pad that 45 with 0s and of course add that colon. Is 
> there a way I
> > > can do that in XSL ?
> > 
> > Of course, but first one needs to know how other times are 
> represented. Is
> > 01:30 represented as "01:30", as "0130", as "90", or in 
> some other way? And
> > is 00:05 represented as "5" or as "05"?
> > >
> > >  Furthermore, in the same repsonse, I have a string of the format
> > > YYYYNYY [chars may be either Y or N], also respresented as a free
> > > format string. This represents the days of the week starting from
> > > Sunday...  Now I need to take each char, and replace it with a <TD
> > > color="green">S</TD> if it is Y, and <TD>S</TD> if it is N.
> > >
> > >  Anyway I can do that in XSL ?
> > >
> > 
> > Sure. In XSLT 2.0 do
> > 
> > <xsl:for-each select="1 to 7">
> >   <TD>
> >     <xsl:if test="substring($in, ., 1) = 'Y'">
> >       <xsl:attribute name="color">green</xsl:attribute>
> >     </xsl:if>
> >     <xsl:text>S</xsl:text>
> >   </TD>
> > </xsl:if>
> > 
> > In 1.0 the simplest solution is probably simply to unfold 
> the loop, i.e.
> > repeat the content of the above for-each loop seven times 
> changing the
> > second argument of substring() each time.
> > 
> > Michael Kay
> > http://www.saxonica.com/