RE: [xsl] XPath query syntax

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Subject: RE: XPath query syntax
From: "Aron Bock" <aronbock@xxxxxxxxxxx>
Date: Wed, 18 May 2005 23:24:37 +0000

Jon, some variant of this should work. You may also want to use normalize-space().

<?xml version="1.0" encoding="iso8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml"/>

   <xsl:template match="/">
       <xsl:for-each select="/textarea/node()[name() != 'br']">
           <line><xsl:copy-of select="."/></line>
       </xsl:for-each>
	</xsl:template>

</xsl:stylesheet>

From: jpk <jopaki@xxxxxxxxx>
I have source XML:

<textarea>
  line 1<br/>
  line 2<br/>
  line 3<br/>
  line 4<br/>
</textarea>

How do I query for each of the line texts?  That is, I
need to get each text [node] that preceeds all <br>
tags.

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Current Thread
XPath query syntax jpk - 18 May 2005 23:06:49 -0000 Aron Bock - 18 May 2005 23:24:53 -0000 <= Jay Bryant - 19 May 2005 03:49:15 -0000 Aron Bock - 19 May 2005 03:53:49 -0000 David Carlisle - 19 May 2005 09:06:27 -0000 Aron Bock - 19 May 2005 11:58:21 -0000

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