<xsl:number/> with no attributes will give you what you want.

Michael Kay
http://www.saxonica.com/

 

> -----Original Message-----
> From: c p [mailto:bugs75il@xxxxxxxxx] 
> Sent: 05 May 2005 18:07
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Node position and numbering.
> 
> Hello all,
> 
> I have following XML:
> -----------------------------------------
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <service>
>     <title>Printing the Page</title>
>     <somenode>node content might go here.</somenode>
>     <step>Go to File menu</step>
>     <step>Select Print</step>
>     <step>Click Print</step>
>     <somenode>you are all done.</somenode>
> </service>
> 
> -----------------------------------------
> As you can see the XML has a <service> node with a
> whole bunch of other child nodes.  Out of all the
> child nodes, I am interested in getting the position
> for <step> nodes only.  Its pretty simple but there's
> a twist.  In the example above if I did
> <xsl:apply-templates match="service"/>  and then for
> each child node I did a position() then it would give
> me numbers 2,4,and 5 for the <step> nodes.  However
> thats not what I want.  I want it to give me numbers
> 1,2,3 for the <step> nodes.  The way I can get that is
> by doing <xsl:apply-templates match="service/step"/>,
> unfortunately due to the complexity of my XSL and XML
> structure I cannot do that.  Is there a way to achieve
> this so I can get an output that will look like this:
> 
> ---------------------------------------------
> 1. Go to File menu
> 2. Select Print
> 3. Click Print
> ---------------------------------------------
> 
> Note:  Its not always guaranteed that the first <step>
> node will start after <title> node or any other node. 
> It could be random.
> 
> Any help would be appreciated.
> 
> Thx,
> C
> 
> 
> 
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