Subject: Re: xsl templates match does not work
From: josh higgins <doopsterus@xxxxxxxxx>
Date: Wed, 6 Apr 2005 09:49:53 -0700 (PDT)
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will it matter if I have a row element is a different
item in my xml? I suppose it would so I should use my
xpath.
Thanks Buddy!
--- David Carlisle <davidc@xxxxxxxxx> wrote:
>
> > I am calling it as follows.
>
> I thought you might be:-)
>
> <xsl:template match="/">
>
> so here the current node is the root node.
> and that is still the case here
>
> <xsl:call-template name="summaryTable"/>
>
> so you need to use any XPath's relative to that so
> header/row/total_due
> not just total_due
>
> Or perhaps simpler change
>
> <xsl:template name="summaryTable">
>
>
> to
>
> <xsl:template match="row">
>
> and change
>
> <xsl:call-template name="summaryTable"/>
>
>
> to
>
> <xsl:apply-templates select="header/row"/>
>
> so that the current node when your template is
> executed is the row node.
>
> David
>
>
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