Re: [xsl] grouping/position problem

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Subject: Re: grouping/position problem
From: Bruce D'Arcus <bdarcus@xxxxxxxxx>
Date: Sat, 23 Apr 2005 06:10:06 -0400

On Apr 23, 2005, at 4:48 AM, Michael Kay wrote:

Assuming $NiQ is a member of current-group(), then you only need to test "$NiQ is not the first in the group", because that implies that there is more than one node in the group. So:

test="not($NiQ is current-group()[1])

Thanks.

But now a dumb question: how do I specify $NiQ? What the expression (or other code) that allows me to define "the member of a current-group()"? Here's the relevant bit, but I've got it wrong:

<xsl:template match="mods:modsCollection" mode="sort_author-year"> <xsl:variable name="bibrefs" select="mods:mods"/> <xsl:for-each-group select="$bibrefs" group-by="bib:grouping-key(.)"> <xsl:sort select="current-grouping-key()"/> <xsl:variable name="author-shorten" select="test="not(. is current-group()[1])"/> 

Bruce

Current Thread

Re: grouping/position problem, (continued)
- Bruce D'Arcus - 23 Apr 2005 10:10:31 -0000 <=
  - Bruce D'Arcus - 23 Apr 2005 12:00:02 -0000
  - Michael Kay - 23 Apr 2005 14:33:15 -0000
- Bruce D'Arcus - 23 Apr 2005 20:35:41 -0000
  - Bruce D'Arcus - 23 Apr 2005 23:40:58 -0000

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RE: grouping/position problem, Michael Kay	Thread	Re: grouping/position problem, Bruce D'Arcus
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