Subject: RE: Common Element Solution (XSL 2.0)
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 23 Mar 2005 10:06:46 -0000
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> <tables>
> <table name="table1">
> <column name="col1"/>
> <column name="col2"/>
> <column name="col3"/>
> <column name="col4"/>
> </table>
> <table name="table2">
> <column name="col1"/>
> <column name="col2"/>
> <column name="col5"/>
> <column name="col6"/>
> </table>
>
> Yes, the basics are clear. Your last line(s) were
> you want something like
>
> count(current-group()/parent::table) = $number-of-tables
>
> relying on the fact that "/" eliminates duplicates.
>
>
> My question was, how does the '/' eliminate duplicates?
> That's the bit I don't understand.
If the input is
> <table name="table1">
> <column name="col1"/>
> <column name="col2"/>
> <column name="col3"/>
> <column name="col4"/>
> </table>
> <table name="table2">
> <column name="col1"/>
> <column name="col2"/>
> <column name="col5"/>
> <column name="col5"/>
> </table>
then when processing col5, count(current-group()) will be 2, but
count(current-group()/parent::table) will be 1, because both columns in the
group have the same parent element.
Michael Kay
http://www.saxonica.com/
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