Hello Joris,

Thank you for your prompt reply. The solution works well.

Being new to XSLT I'm a little unsure of exactly what the pattern in the
'use' attribute value in the xsl:key element is doing.

Could you please explain  it in a little more detail.

Thanks

Paul 

-----Original Message-----
From: Joris Gillis [mailto:roac@xxxxxxxxxx] 
Sent: 15 February 2005 18:48
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  FW: Dealing with mixed content

Tempore 19:31:36, die 02/15/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx
scripsit Paul Clarke
<pclarke@xxxxxxxxxxxxxxxx>:

> Hello,
>
> Apologies inadvance for the 'XSL 101' nature of this question but I'm 
> new to XSL.
>
> I receive XML from an automate conversion process, over which I have 
> no control.
>
> Example:
>
> 	<block >Text <font font-weight="bold">more text</font> more 
> text<sr/>more text. <hr/>more text <sr/>more text.</block>
>
> The <sr/> elements can be ignored but the <hr/> element indicates that 
> an exisitng <P> element should be terminated and a new <P> element
started.
>
> From the above sample the output would be:
>
> 	<P>Text <f>more text</f> more text more text. </P>
> 	<P>more text more text</P>
>
Hi,

This is a grouping problem. Numerous techniques are available for solving
problems like this.

Here you have one:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"  
version="1.0">
<xsl:output method="xml" indent="yes"/>

<xsl:key name="group" match="node()" use="generate-id((.. |
preceding-sibling::hr)[last()])"/>

<xsl:template match="block">
	<xsl:copy>
		<xsl:for-each select="hr|.">
			<p>
				<xsl:apply-templates
select="key('group',generate-id())"/>
			</p>
		</xsl:for-each>
	</xsl:copy>
</xsl:template>

<xsl:template match="sr | hr"/>

<xsl:template match="font">
	<f>
		<xsl:apply-templates/>
	</f>
</xsl:template>

</xsl:stylesheet>


regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
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