Where is $p1 defined? it must be defined before <xsl:call-template> as a
variable. By using <xsl:with-param> you are just indicating the you are
passing that value to the parameters in f template, not declaring it.

-----Mensaje original-----
De: Wim Janssen [mailto:Wim.Janssen@xxxxxxxxxxxxxxxxx]
Enviado el: Jueves, 03 de Febrero de 2005 14:46
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Asunto:  with-param problem


Hi,

I'm working on a master thesis about XSLT.

I found a problem and I don't know wether it is a bug in saxon (version 8.0).

Take a look a this little program

 <xsl:template match="/a">
  <xsl:element name="S">
   <xsl:call-template name="f">
    <xsl:with-param name="p1" select="3"/>
    <xsl:with-param name="p2" select="$p1 + 2"/>
   </xsl:call-template>
  </xsl:element>
 </xsl:template>

 <xsl:template name="f">
  <xsl:param name="p1"/>
  <xsl:param name="p2"/>
 </xsl:template>

The problem is the param named "p2".  It uses param "p1".  Why is that not
allowed in XSLT? Or is it maybe a bug in Saxon?

I'm sorry for my terrible English!

greetings

Wim Janssen