Please use exclude-result-prefixes
<xsl:stylesheet version="1.0"
  xmlns:exslt="http://exslt.org/common"
  xmlns:java="http://xml.apache.org/xslt/java"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  exclude-result-prefixes="exslt java" >

The XSLT 1 spec says..
When a stylesheet uses a namespace declaration only
for the purposes of addressing the source tree,
specifying the prefix in the exclude-result-prefixes
attribute will avoid superfluous namespace
declarations in the result tree.

The value of exclude-result-prefixes is a
whitespace-separated list of namespace prefixes.

Regards,
Mukul

--- "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> wrote:

> My stylesheet generates an XML document. But the xml
> contains namespace declarations, which I don't want.
> The header part of my stylesheet is:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> 	xmlns:exslt="http://exslt.org/common"
> 	xmlns:java="http://xml.apache.org/xslt/java"
> 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  	<xsl:output method="xml" version="1.0"
> encoding="UTF-8" 
> 	indent="yes"/>
> 
> The glimpse of xsl producing xml is:
> <reportdetails>
> 	<xsl:attribute name="name"><xsl:text>Chart
> List</xsl:text></xsl:attribute>
> 	<xsl:attribute name="generated"><xsl:value-of
> select="java:java.util.Date.new()"/></xsl:attribute>
> 	<xsl:attribute name="user"><xsl:value-of
> select="$username"/></xsl:attribute>
> </reportdetails>
> 
>  and the output is:
> <?xml version='1.0' encoding='UTF-8' ?>
> <reportdetails
> xmlns:java="http://xml.apache.org/xslt/java"
> xmlns:exslt="http://exslt.org/common" name="Chart
> List" generated="Tue Feb 15 13:00:54 GMT+05:30 2005"
> user=""/>
> 
> I don't want namespace declaration in the xml file.
> Any help would be appreciated.
> regards,
> Ranjan
> 
> 
> 		
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