The xsl:copy-of instruction is only useful where you want to do an exact
copy. The standard way to do a transformation where the output is nearly the
same as the input is to start with the identity template rule:

<xsl:template match="*">
  <xsl:copy>
  <xsl:copy-of select="*"/>
  <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

and then override it for elements that need to be modified:

<xsl:template match="MenuData">
  <xsl:copy>
  <xsl:value-of select="normalize-space(.)"/>
  </xsl:copy>
</xsl:template>

Michael Kay
http://www.saxonica.com/


> -----Original Message-----
> From: Antsnio Mota [mailto:amsmota@xxxxxxxxx]
> Sent: 25 January 2005 19:12
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Removing line-feeds on a imported tree via document
>
> Here's another interesting one. In my XSLT i have at some point
>
> <xsl:copy-of select="$xmldoc/Menus/Menu" />
>
> working ok, EXCEPT sometimes i get things like
>
> <Menu>
> <Menu_K>X00066</Menu_K>
> <Titulo>(Cada Utente)</Titulo>
> <MenuData>SELECT Utente_K, NomeLogin
> FROM Utente
> WHERE UtenteTipo='U'</MenuData>
> <MenuTipo>TXT</MenuTipo>
> </Menu>
>
> Notice the line breaks on MenuData, that is causing me problems later
> on. So i want to get rid of then. I've tryed using
>
> <xsl:copy-of select="normalize-space($xmldoc/Menus/Menu)" />
>
> because i don't understand nothing of this, but soon realise the
> error, so i went back and define a template
>
> 	<xsl:template match="MenuData">
> 		<xsl:copy><xsl:value-of
> select="normalize-space(.)"/></xsl:copy>
> 	</xsl:template>
>
> but did no good, cause it seems that only match the original MenuDatas
> and not the imported ones.
>
> Any sugestions? Thanks.