<xsl:variable name="mainXML_node" select="document('../XML/PM-EA-AA_IA_PA_TA.xml')"/>
	(...)
	<xsl:for-each-group select="concat($mainXML_node,$path)" group-by="@SAObjName">
	(...)

<xsl:variable name="xpath">
  <xsl:text>document('../XML/PM-EA-AA_IA_PA_TA.xml')</xsl:text>
  <xsl:value-of select="@XPath" />
</xsl:variable>

Cheers,
Geert

Hello,

No, the /Classes/Clas... Found within the @Xpath attribute is simply a string. The idea is to find a way to concatenate a root node and this xpath string, then evaluate it. -> document(Xxx.xml)/Classes/Class/...
					        (     is a node       )(    is a string    )  --> (must be a nodeset)

-----Urspr|ngliche Nachricht-----
Von: Geert Josten [mailto:Geert.Josten@xxxxxxxxxxx] Gesendet: Montag, 3. Januar 2005 11:31
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: Re: Xpath as variable - bis

XPath="/Classes/Class/SADefinition[starts-with(@SAObjName,'app_') or
starts-with(@SAObjName,'apx_') or starts-with(@SAObjName,'apt_')]"/>
(...)

I suspect that the path '/Classes/..' is not evaluated with the external document as context, but the one passed from source of command-line. But I'm not a Saxon expert.

Have you tried relative paths?

Cheers,
Geert

--
Geert.Josten@xxxxxxxxxxx
IT-consultant at Daidalos BV, Zoetermeer (NL)

http://www.daidalos.nl/
tel:+31-(0)79-3316961
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