Re: [xsl] xsl:sort now working under unix

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Subject: Re: xsl:sort now working under unix
From: Anton Triest <anton@xxxxxxxx>
Date: Thu, 23 Dec 2004 00:59:41 +0100

Hi Sylvia,

<xsl:for-each select="/runs/case">  <xsl:apply-templates select="document(@filename)/case"> <xsl:sort select="/case/status" data-type = "text" order="descending"/> </xsl:apply-templates> </xsl:for-each>

xsl:apply-templates sets the context node to a case element, and status is a child element of case, so you'll need <xsl:sort select="status" .../>

I don't think a sort select expression should ever start with "/": it is a valid XPath expression but it's "fixed" (ie. it doesn't change over the various elements you apply-templates to.)

Cheers,
Anton

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xsl:sort now working under unix Sylvia Murphy - 22 Dec 2004 17:28:25 -0000 Anton Triest - 22 Dec 2004 20:20:51 -0000 Sylvia Murphy - 22 Dec 2004 23:01:57 -0000 Anton Triest - 23 Dec 2004 00:00:02 -0000 <=

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