Subject: Re: Re: [xslt transform & grouping] Using the Muenchian Method?
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 5 Oct 2004 16:06:51 +0100
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> Use this XSLT to genterate new XML file by using specified XML input
> file:
clearly that will generate an error as it uses a kety that is not
defined, as I pointed out in the message that you quoted.
As such it will generate no output.
If you fix that then you will get no error
and if you fix <xsl:param name="filter" select="food"></xsl:param>
to have 'food' then you will get the output that I also posted in that
message, assuming you have a conforming processor.
If you leave $filter with that value you'll just get an empty Documents
element as $filter would be an empty node set as previously explained.
David
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