this is the full xsl code:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<!-- overload the text template,
		do NOT automatically pass-thru text -->
	<xsl:template match="text()">
	</xsl:template>
	<xsl:template match="/">
		<xsl:apply-templates/>
	</xsl:template>
	<!-- for all SEG*/NAME elements, display the name, followed by a * -->
	<xsl:template match="*[starts-with(name(), 'SEG')]/NAME">
		<xsl:value-of select="."/><xsl:text>*</xsl:text>
	</xsl:template>
</xsl:stylesheet>

will that not go thru and apply all the templates that have matches?

-L

> -----Original Message-----
> From: Jarno.Elovirta@xxxxxxxxx [mailto:Jarno.Elovirta@xxxxxxxxx]
> Sent: Thursday, September 16, 2004 9:48 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  not getting expected matches
>
>
> Hi,
>
> > okay, the expression I'm using is:
> >
> > <xsl:template match="//*[starts-with(name(), 'SEG')]/NAME">
> > 	<xsl:value-of select="."/><xsl:text>*</xsl:text>
> > </xsl:template>
> >
> > I'm thinking that this should return me the text of the
> > 'NAME' child of all of the elements that start with 'SEG'
> > correct? but I have this as my XML...
>
> No, you don't have an expression to select anything, but
> rather you have a match pattern that matches a NAME element
> whose parent element's name starts with "SEG".
>
> Cheers,
>
> Jarno