Subject: Re: Sum produces NaN
From: "cking" <cking@xxxxxxxxxx>
Date: Mon, 13 Sep 2004 20:24:51 +0200
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Hi James,
I'm not sure why you use named templates, can't you just say
<xsl:value-of select="sum(a/b/data)"/> ?
That would give you the sum of all <data> records,
but indeed returns NaN if one of them is empty.
To solve this, you can narrow your selection to those
<data> elements whose content is not empty:
<xsl:value-of select="sum(a/b/data[.!=''])"/> or
<xsl:value-of select="sum(a/b/data[text()])"/>
That should return "8" for your input
HTH
Anton Triest
James Steven wrote:
>
> Hello
> To add a column of numbers I am using the xsl below. However if there is
> one value missing in the column then the xsl produces NaN.
>
> eg. Below is xml with a value missing in last <data>. I then use the xsl
> below to add all <data> values but receive NaN because of the missing value.
> If all <data> tags have value then the sum works. Please could anyone show
> how to resolve this. Any help greatly appreciated.
>
> <a>
> <b>
> <data>1</data>
> </b>
> <b>
> <data>2</data>
> </b>
> <b>
> <data>5</data>
> </b>
> <b>
> <data></data>
> </b>
> </a>
>
>
> <xsl:template name="orderlist.sum.edit">
> <xsl:param name="set-of-order"/>
> <xsl:variable name="sumorg">
> <xsl:call-template name="orderlist.sum">
> <xsl:with-param name="set-of-order" select="$set-of-order"/>
> </xsl:call-template>
> </xsl:variable>
> <xsl:value-of select='format-number($sumorg, "####,###,##0.00")'/>
> </xsl:template>
>
> <xsl:template name="orderlist.sum">
> <xsl:param name="set-of-order"/>
> <xsl:choose>
> <xsl:when test="$set-of-order">
> <xsl:variable name="first">
> <xsl:apply-templates select="$set-of-order[1]/data"/>
> </xsl:variable>
> <xsl:variable name="rest">
> <xsl:call-template name="orderlist.sum">
> <xsl:with-param name="set-of-order" select="$set-of-order[position()
> != 1]"/>
> </xsl:call-template>
> </xsl:variable>
> <xsl:value-of select="$first + $rest"/>
> </xsl:when>
> <xsl:otherwise>0</xsl:otherwise>
> </xsl:choose>
> </xsl:template>
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