Subject: RE: How to: Reference to the current Nodeset while processing through another one
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 29 Sep 2004 10:16:20 +0100
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My immediate answer to the question in your subject line is "use variables".
Now I see:
> I want to get all other "Value" items, having the same
> id. I want to
> get them without using a referenc variable.
and my immediate reaction is: why? It's like saying you want to eat
spaghetti, and you want to do it without using a fork.
>
> I tried:
> <xsl:for-each select="//Value[@id = Value/@id]">
> <!-- Do something -->
> </xsl:for-each>
>
> But this returned all Values having a attribut "id".
I'm surprised this would return anything. It asks for all Value elements
that have an @id attribute and that have a child Value element with the same
value of @id.
>
> If I declare a variable with the value of "id"
> <xsl:variable name="v_id">
> <xsl:value-of select="@id"/>
> </xsl:variable>
It's better to write this as
<xsl:variable name="v_id" select="@id"/>
but in this case either will work.
> and process though the other nodes by using the variable it works:
> <xsl:for-each select="//Value[@id = $v_id]">
> <!-- Do something -->
> </xsl:for-each>
>
> In this case I get all "Value" nodes having a "id" of "123".
> But how can I do this without using a variable?
If you really hate variables that much, you can often get by with current(),
which is in effect a built-in variable set to the node that was the current
node at the outermost level of the XPath expression. So you can write
<xsl:for-each select="//Value[@id = current()/@id]">
Incidentally, this would be much faster with keys.
Michael Kay
http://www.saxonica.com/
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