RE: Re: [xsl] finding position in list of siblings

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Subject: RE: Re: finding position in list of siblings
From: cknell@xxxxxxxxxx
Date: Fri, 09 Jul 2004 16:31:52 -0400

You're welcome. For the record, I made a typo when left out the closing square bracket in the predicate. Here is the correct template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER'])" />
</xsl:template>


--
Charles Knell
cknell@xxxxxxxxxx - email

-----Original Message-----
From:     John C Cartwright <John.C.Cartwright@xxxxxxxx>
Sent:     Fri, 09 Jul 2004 13:29:36 -0600
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Re:  finding position in list of siblings

works perfectly! Thanks for the prompt response.

-- john

cknell@xxxxxxxxxx wrote:

Try this template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER')" />
</xsl:template>

-- ==================================================== John Cartwright Associate Scientist Geospatial Data Services Group CIRES, National Geophysical Data Center/NOAA (303) 497-6284 John.C.Cartwright@xxxxxxxx ====================================================

Current Thread
Re: finding position in list of siblings, (continued) Wendell Piez - Fri, 09 Jul 2004 15:57:58 -0400 David Carlisle - Sat, 10 Jul 2004 17:13:48 +0100 cknell - Fri, 09 Jul 2004 15:13:00 -0400 John C Cartwright - Fri, 09 Jul 2004 13:29:36 -0600 cknell - Fri, 09 Jul 2004 16:31:52 -0400 <=

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Re: finding position in list , John C Cartwright	Thread	Muenchian grouping: help with, Justin Anderson
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