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Ranjan,
But I'm not sure this is going to work (have you tested it?): count(connectivity//*[@*[not(local-name() = 'sharedsource')]]) for the stated requirement how to find out [the] number of elments which [do] not have a particular attribute? Parsing the XPath into English ... count() counts a set of nodes connectivity expands to child::connectivity ('connectivity' child elements of the context node) ... this could be what you want, depending on the input and the context node being matched connectivity//* expands to child::connectivity/descendant-or-self::node()/* namely any element descendant of the 'connectivity' children [@*] "which has an attribute" [not(local-name() = 'sharedsource')] "whose local name is not 'sharedsource'" In other words, the expression returns the count of all descendants of 'connectivity' children that have an attribute whose local name is not 'sharedsource'. This is different from all elements that have no 'sharedsource' attribute. To cut to the chase, the latter would be count(//*[not(@sharedsource)]) which returns the count of all element descendants of the root that have no 'sharedsource' attribute. Its long-syntax form is count(/descendant-or-self::node()/*[not(attribute::sharedsource)]) Cheers, Wendell At 08:36 AM 7/7/2004, 'twas written: > <xsl:variable name="sharedcount1" > select="count(connectivity//*[@*[not(local-name() = > 'sharedsource')]])"/> ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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