[xsl] how to replace a part of a string with a newline??

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Subject: how to replace a part of a string with a newline??
From: Varun Suri <varunsuri@xxxxxxxxxxxxxxx>
Date: Tue, 13 Jul 2004 13:20:45 +0530

Hi

Ive got this string :

Importer__OPT__Trading Company__OPT__Service Provider

How do i make it equivalent to
- Importer
- Trading Company
- Service Provider

Ive tried using translate function, but it replaces all instances of the letters O,P,T as well.I did something like:

translate(text(),'__OPT__',':')

It gives the following output is Importer:rading Company:Service rovider which i dont want.

Any easy way to do it??

Thanks in advance
Regards
Varun

Current Thread
how to replace a part of a string with a newline?? Varun Suri - Tue, 13 Jul 2004 13:20:45 +0530 <= Mukul Gandhi - Tue, 13 Jul 2004 01:57:39 -0700 (PDT) Varun Suri - Tue, 13 Jul 2004 14:54:07 +0530 Arulraj - Tue, 13 Jul 2004 02:30:50 -0700 (PDT) Peter Flynn - Tue, 13 Jul 2004 11:01:49 +0100

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