Hi,

> <xsl:stylesheet version="1.0"
>   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
>   xmlns:xhtml="http://www.w3.org/1999/xhtml";>

There's a SEMICOLON before the GREATHER-THAN SIGN, that makes your XSLT stylesheet ill-formed XML.

>     <xsl:output method="text"/>

Your question subject says you want to generate HTML, but here you're using text output method. It should be html if you want to generate HTML.
 
>    <xsl:template match="xhtml:title">
> 
>         <xsl:text>title: </xsl:text>
>         <xsl:value-of select="."/>
>         <xsl:text>&#10;</xsl:text>
>     </xsl:template>
> 
>     <xsl:template match="p">

This will not match your source because in your source the p elements are in XHTML namespace.

>         <xsl:text>paragraph "</xsl:text>
>         <xsl:value-of select="@name"/>
>         <xsl:text>": </xsl:text>
>         <xsl:value-of select="."/>
>         <xsl:text>&#10;</xsl:text>
>     </xsl:template
> </xsl:stylesheet>
> 
> I want to parse it and get the result as 
> a HTML page.

Then you need to generate the html etc. elements in one of your templates.

> I parse it via msxsl parser, but I get this error
> 
> D:\deepak\buildProcess_2\_tools>msxsl test.xhtml
> test.xsl -o test.html
> 
> Error occurred while parsing document.
> 
> Code:   0xc00ce50a
> URL:   
> file:///D:/deepak/buildProcess_2/_tools/test.xhtml
> Line:   2
> Column: 70
> The character '>' was expected.

Parser reports the well-formedness errors in your stylesheet.
 
> Also how and where should I include the statement
> manually inside the
> xhtml file to indicate to parse via the xsl file.
> 
> In xml files we include the statement 
> <?xml-stylesheet type="text/xsl" href="bcel-fb8.xsl"?>
> 
> Is parsing a XHTML via xsl a similar process?

Just serve the XHTML document using MIME-type "application/xhtml+xml" or e.g. "text/xml" and the browsers will process it as an XML document-if they support XML and XSLT.

Cheers,

Jarno