Subject: RE: Getting position while ignoring empty elements
From: "Andrew Welch" <AWelch@xxxxxxxxxxxxxxx>
Date: Tue, 27 Apr 2004 14:34:16 +0100
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> Is it possible to find the position of an element while ignoring all
> elements containing no text. For example, given the following:
>
> <furniture>
> <item>table</item>
> <item/>
> <item>chair</item>
> </furniture>
>
> I would like to output:
>
> Furniture
> 1. table
> 2. chair
Lots of ways, one being:
<xsl:template match="furniture">
<xsl:for-each select="item[child::node()]">
<xsl:value-of select="position()"/>. <xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>
The for-each will iterate over each <item> node that has a child node
(whitespace included). The function position() will return the position
of the node within the set selected by the for-each.
cheers
andrew
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Andrew Welch - Tue, 27 Apr 2004 09:34:32 -0400 (EDT) <=
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