hi,
do i understand your intention as:

- give any of the 3 links an URL parameter that should then be passed to the XSL like
	<a><xsl:attribute> name="href">test.xml?evaluate=admin</xsl:attribute>evaluate the admin</a></p>

- XSL should then display only relevant data on the URL parameter?


chris


> -----Urspr|ngliche Nachricht-----
> Von: Markus Hanel [mailto:markus.hanel@xxxxxx]
> Gesendet: Dienstag, 30. Mdrz 2004 13:24
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: Re: AW:  change a attribute with a link?
> 
> 
> hello,
> 
> the 3 links and the template " <xsl:template 
> match="node[attribute::type =
> 'admin']">
> " are in one stylesheet. the links should evaluate the same 
> xml file and
> there should be a possibility (I hope so) to change the 
> attribute "type" at the
> xslt element " apply-templates and template". is there a xslt 
> element or x
> path function that can transport a parameter that is given at a link?
> So when I change the attribute "type" to interviewer all 
> pers_datas of the
> <node type="department">
> should be catched.
> 
> > do you want to open the link with a parameter which type of 
> pers_data you
> > want to show or is this all on one file?
> > 
> > in case of the parameter you need to provide information 
> which environment
> > you work in (servlet?)
> > 
> > if you want to put it all in one file you could do something like:
> > 
> > <xsl:template match="/">
> > 	<!-- this is slow, better to select the proper nesting 
> if possible -->
> > 	<xsl:apply-templates select="//pers-data"/>
> > </xsl:template>
> > 
> > <xsl:template match="pers_data">
> > 	<p>
> > 		<!-- @ is the same as attribute:: but i think 
> much neater cause it is
> > shorter -->
> > 		<a href="test.xml?param={parent::node/@type}">
> > 			<xsl:value-of select="parent::node/@type"/>
> > 		</a>
> > 	</p>
> > </xsl:template>
> > 
> > 
> > is that what you were trying to do?
> > chris
> > 
> > 
> > 
> > > -----Urspr|ngliche Nachricht-----
> > > Von: Markus Hanel [mailto:markus.hanel@xxxxxx]
> > > Gesendet: Dienstag, 30. Mdrz 2004 10:21
> > > An: xsl mailinglist
> > > Betreff:  change a attribute with a link?
> > > 
> > > 
> > > hello,
> > > I want to list some informations of pers_datas of some nodes. 
> > > The routine is
> > > equal for the attribut "admin", "interviewees" and 
> > > "interviewer" of this
> > > nodes. My idear is to make 3 links, every link opens the same 
> > > file and evaluates
> > > with one of the attributes: admin, interviewees or 
> > > interviewer. Therefore I
> > > had to change the value of "attribute::type" of the xslt elements:
> > > apply-templates and template. Is there a possibility to 
> arange this? 
> > > 
> > > xml file
> > > <node type="admin">
> > >   <pers_data></pers_data>
> > >     <node type="school">
> > >       <node type="interviewees">
> > >         <pers_data></pers_data>
> > >         <pers_data></pers_data>
> > >         <pers_data></pers_data>
> > >       </node>
> > >       <node type="department">
> > >         <node type="interviewer">
> > >           <pers_data></pers_data>
> > >           <pers_data></pers_data>
> > >           <pers_data></pers_data>
> > >         </node>
> > >         ...
> > > 
> > > 
> > > xsl file
> > > <xsl:stylesheet>
> > > ...
> > > <p><a><xsl:attribute 
> name="href">test.xml</xsl:attribute>evaluate the
> > > admin</a></p>
> > > <p><a><xsl:attribute 
> name="href">test.xml</xsl:attribute>evaluate the
> > > interviewees</a></p>
> > > <p><a><xsl:attribute 
> name="href">test.xml</xsl:attribute>evaluate the
> > > interviewer</a></p>
> > > 
> > > ...
> > > <xsl:apply-templates 
> > > select="descendant-or-self::node[attribute::type =
> > > 'admin']" />
> > > ....................................should change to 
> > > [attribute::type =
> > > 'interviewees']
> > > <xsl:template match="node[attribute::type = 'admin']">
> > > ...
> > > </xsl:template>
> > > </xsl:stylesheet>
> > > 
> > > Many thanks
> > > markus