Thank you,
thats the solution of my problem!
markus

> concat() creates a string. You seem to be using it to construct an XPath
> expression. You won't get a node-set unless you evaluate this XPath
> expression, which you aren't even attempting to do. 
> 
> Standard XSLT doesn't allow you to evaluate an XPath expression
> constructed
> dynamically as a string, but some products have an extension
> (xx:evaluate())
> that permits it.
> 
> But I don't think you need dynamic evaluation here. You can use the
> standard
> technique:
> 
> Select="$self_quirxi/globals/pers_datas/pers_data/*[name()=$qadmin_table]"
> 
> Michael Kay
> 
> # -----Original Message-----
> # From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-
> # list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Markus Hanel
> # Sent: 05 March 2004 07:21
> # To: xsl mailinglist
> # Subject:  concat - node set or a string
> # 
> # I would like to write a node set that allows me to automatically show
> the
> # elements of a pers data.
> # Therefore I defined 2 variables: self_quirxi and qadmin_table
> # ...
> # <xsl:variable name="self_quirxi"
> # select="document('/qxml/quirxi.xml')/quirxi" />
> # ...
> # <xsl:variable name="qadmin_table" select="." /> selects surname,
> # lastname,...
> # 
> # Here I want to give out the node set, but it is only a string!
> # <xsl:value-of
> #
> select="concat($self_quirxi,'/globals/pers_datas/pers_data/',$qadmin_table
> # )" />
> # 
> # Where is the bug?
> # markus
> # 
> # 
> #  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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