Subject: Re: replacing parts of a string
From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx>
Date: Thu, 15 Jan 2004 20:40:42 +0100
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"Jonny Pony" <jonnypony666@xxxxxxxxxxx> wrote in message
news:Law14-F78xpTljBOh8s0000768c@xxxxxxxxxxxxxx
> Hi,
>
> forgot the previous mail:
>
> How and where must I customize your template to pass only a string.
> Something like:
>
> <xsl:call-template name="LongString">
> <xsl:with-param name="stringIn"><xsl:value-of
select="."/></xsl:with-param>
> </xsl:call-template>
>
> Thanks
> Jonny
You already have this in the example:
<xsl:call-template name="str-map">
<xsl:with-param name="pFun" select="$vTestMap"/>
<xsl:with-param name="pStr" select="."/>
</xsl:call-template>
So, just specify the value of the "pStr" parameter, e.g.:
<xsl:with-param name="pStr"
select="76rt,dsfg,dsfg"/>
Dimitre Novatchev.
FXSL developer,
http://fxsl.sourceforge.net/ -- the home of FXSL
Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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