Subject: Re: recursive addition
From: annirack@xxxxxxx
Date: Wed, 14 Jan 2004 16:46:50 -0800
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I'm really not doing very well here, am I?
I said *IF* it were a nested, rather than flat, file structure, I could do that. As it is, I cannot.
Perhaps the way to go is to write an xslt to convert from the flat file format to a nested one.
--Brendan
----- Original Message -----
From: "M. David Peterson" <m.david@xxxxxxxxxx>
Date: Wednesday, January 14, 2004 3:56 pm
Subject: Re: recursive addition
> If all the folders within a root folder have the same 'id' (what
> would be
> the point of having the 'id' attribute on the child folder
> elements?) you
> could do this:
>
> <xsl:value-of select="sum(//folder[@id = 'dir0']/@files)"/>
>
> If they dont then this would do the trick:
>
> <xsl:value-of select="sum(//folder[@id = 'dir0']/@files) +
> sum(//folder[@id= 'dir0']//folder/@files)"/>
>
> Im even more confused from your explanation than I was the first
> time around
> but I think one of these will help you get to where you want to go.
>
> Best of luck,
>
> M.
>
> ----- Original Message -----
> From: <annirack@xxxxxxx>
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Wednesday, January 14, 2004 3:58 PM
> Subject: Re: recursive addition
>
>
> > > The semantics are most definitely unclear but im assuming that you
> > > know what
> > > you want to gain out of adding dir2 and dir3.
> >
> > I apparently didn't explain myself well at all. Sorry about
> that, here's
> another attempt:
> >
> > I have an XML file that represents a file system, and has a flat
> filestructure.
> > All folder nodes are siblings and all file nodes are children of
> a folder
> node. To represent a folder being within another folder, a file
> node can be
> a link to a folder node.
> >
> > Each folder node has an attribute that indicates how many files it
> contains.
> >
> > I want to know how many files are in all the subfolders of a
> given folder.
> >
> > I don't know if this is even possible in xsl 1.0
> >
> > If it were not a flat file structure, it would seem easier...
> since I
> could select all subfolders using "root/folder[@id="some
> id"]//folder" and
> some form of recursive algorithm could probably handle the rest.
> >
> > --Brendan
> >
> >
> > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-
> list>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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