Subject: RE: Sorting results by output of a conversion template
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Fri, 9 Jan 2004 09:56:53 -0000
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> I need to be able to sort my results by the output of this
> template. So...is there a way using XSL:SORT to call a
> template (like the one above) and sort the results that way??
Not in 1.0.
You can do it using a 2-phase transformation, where the first phase
writes a temporary tree containing the expanded values, and the second
phase sorts the nodes from the temporary tree (accessed using
exslt:node-set()).
In XSLT 2.0 this becomes easy using a call on an xsl:function from
within the <xsl:sort> select expression.
Michael Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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