if you sort by the reverse of your date(26.11.2003) i.e. 20031126 ....



you can extract and sort using substring on your date i.e.
<xsl:foreach.............
<xsl:sort data-type="number" select="substring(@date,6,4)"/>/<xsl:value-of
select="substring(@date,3,2)"/>/<xsl:value-of select="substring(@date,1,2)"
order="ascending"/>
<xsl:if position()=1>

</xsl:if>

Syntax and substring result is most likely wrong but i think it would work.

PA Sport RnD

Andrew Curry
Software Developer

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----- Original Message ----- 
From: "Iris Benjamin" <Benjamin.Iris@xxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Friday, December 05, 2003 10:16 AM
Subject:  Date variable ?!


> Hello
>
> I have a simple XML document wit lots of elements : "testCase"
> every "testCase" has an attribute such as      startedOn="26.11.2003
> 11:41:30"
> In my xslt programm, I would like to extract the earliest startedOn
> attribute among all the testCase elements.
> That means, look through all the values of the attribute and find a way
tget
> the earliest date.
> (if it is too complicated with the Time, we can only focus on the date)
>
> If you have any idea, I thank you in advance.
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list